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28x^2+37x+12=0
a = 28; b = 37; c = +12;
Δ = b2-4ac
Δ = 372-4·28·12
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-5}{2*28}=\frac{-42}{56} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+5}{2*28}=\frac{-32}{56} =-4/7 $
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